0=16t^2+325t

Solution for 0=16t^2+325t equation:

0=16t^2+325t

We move all terms to the left:

0-(16t^2+325t)=0

We add all the numbers together, and all the variables

-(16t^2+325t)=0

We get rid of parentheses

-16t^2-325t=0

a = -16; b = -325; c = 0;
Δ = b2-4ac
Δ = -3252-4·(-16)·0
Δ = 105625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{105625}=325$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-325)-325}{2*-16}=\frac{0}{-32}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-325)+325}{2*-16}=\frac{650}{-32}
=-20+5/16
$